x(x-1)=2x^2

Solution for x(x-1)=2x^2 equation:

x(x-1)=2x^2

We move all terms to the left:

x(x-1)-(2x^2)=0

determiningTheFunctionDomain
-2x^2+x(x-1)=0

We multiply parentheses

-2x^2+x^2-1x=0

We add all the numbers together, and all the variables

-1x^2-1x=0

a = -1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-1}=\frac{0}{-2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-1}=\frac{2}{-2}
=-1
$